Question

A wire of given material having length l and area of cross-section A, has a resistance of 2 Ω. Find the resistance of another wire of same material having length 2l and are of cross-section A/2.

Answer 1

Answer:

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Answer 2

The new resistance is four times the previous resistance

Explanation:

Resistance (R) = 2 Ω

Area of cross-section = A

Length = L

By Ohm's Law, we know that R = pL/A

So 2 = pL/A -----------------(1)

New area = A/2

New length = 2L

New resistance = Rn = p*2L/ (A/2) = 4 pL/A ---------(2)

Substituting (1) in (2), we get:  

Rn = 4 * pL/A = 4 * 2 = 8Ω

The new resistance is four times the previous resistance.