A wire of given material having length l and area of cross-section A has a resistance of 4ꭥ. What would be the resistance of another wire of the same material having l/2 and area of cross-section 2A?
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Answer:
Given;
L=l,
A=a,
R=4 ohm
Now, R=p*L/A
4=p*L/A.......(i)
Now,
L1=l/2
A1=2a
R'=p*L1/A1
R'=p*l/2/2a
R'=p*2*l/2*a
R'=1*p*l/a......(ii)
R'=1*4............(putting value of i in ii equation R=p*l/a)
R'=4 ohm
Hence, Resistance of another wire is 4 ohm
I hope it is helpful for you
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