Energy ( in eV) of a photon having wavelength of 248 Ao is : ( use hc = 1240 eV. and 1Ao = 10-10 m)
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Answer:
find the energy of a photon you use the Planck Expression:
E
=
h
f
h
is the Planck Constant which =
6.63
×
10
−
34
x
J
.
s
f
is the frequency
This becomes:
E
=
h
c
λ
c
is the speed of light =
3.00
×
10
8
x
m/s
λ
is the wavelength
∴
E
=
6.63
×
10
−
34
×
3.00
×
10
8
490
×
10
−
9
x
J
E
=
4.00
×
10
−
19
x
J
If 1 Coulomb of charge is moved through a potential difference of 1 Volt then 1 Joule of work is done.
The electron volt is the work done in moving 1 electron through a potential difference of 1 Volt.
The charge on the electron is taken here to be
1.60
×
10
−
19
x
C
∴
1
eV
=
1.60
×
10
−
9
x
J
∴
The energy of the electron in electron volts
=
4.00
×
10
−
19
1.60
×
10
−
19
=
2.5
x
eV
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Explanation:
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