Chemistry, asked by ruchikaamishra, 9 months ago

Energy ( in eV) of a photon having wavelength of 248 Ao is : ( use hc = 1240 eV. and 1Ao = 10-10 m)

Answers

Answered by zaid4080
2

Answer:

find the energy of a photon you use the Planck Expression:

E

=

h

f

h

is the Planck Constant which =

6.63

×

10

34

x

J

.

s

f

is the frequency

This becomes:

E

=

h

c

λ

c

is the speed of light =

3.00

×

10

8

x

m/s

λ

is the wavelength

E

=

6.63

×

10

34

×

3.00

×

10

8

490

×

10

9

x

J

E

=

4.00

×

10

19

x

J

If 1 Coulomb of charge is moved through a potential difference of 1 Volt then 1 Joule of work is done.

The electron volt is the work done in moving 1 electron through a potential difference of 1 Volt.

The charge on the electron is taken here to be

1.60

×

10

19

x

C

1

eV

=

1.60

×

10

9

x

J

The energy of the electron in electron volts

=

4.00

×

10

19

1.60

×

10

19

=

2.5

x

eV

Answer link

Explanation:

keep as brainlest plzzz

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