Question

A wire of length 10 cm moves with a speed 10 m/s perpendicular to a magnetic field of intensity 1.0 wbrrr². Calculate the induced e.m.f.

Answer 1

Given :

length=10cm =10 x 10⁻² m

speed= v= 10m/s

B= 1 w/m²

Induced emf=?

e= BVl

=1x10x 10 x10⁻²

=1V

∴Induced emf is 1 v

Answer 2

Answer:

1V

Explanation:

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