Question

metallic rod of length 25 cm moves with a speed 20 m/s perpendicular to- a magnetic field of intensity 2 wb m². Calculate the magnitude of e.m.f.

Answer 1

Given :

length=l=25cm = 25 x 10⁻² m

B= 2 wb/m²

Speed= v= 20 m/s

Formula :

e=BVl

= 2x20x25x 10⁻²

=2x20x25/100

=10V

∴  The magnitude of emf= 10V