Question

A wire of length 100cm is cut into two parts and each part is bent into a square. If the sum of the area of the two squares is 425cm^2, find the lengths of the sides of the two squares.

Answer 1

Answer:

Lengths of the sides of the squares are 5cms and 20 cms.

Step-by-step explanation:

Let x and y, be the length of the two sides of the squares.

So,

x^2 + y^2 = 425cms2 --> (1)

4x + 4y = 100cms --> x + y = 25cms --> x = 25 - y --> (2)

Substitute (2) in (1)

(25-y)^2 + y^2 = 425

625 - 50y + y^2 + y^2 = 425

2y^2 - 50y + 200 = 0

y^2 - 25y + 100 = 0

by Quadratic Formula, y = 20cms

from (2)

4x + 4(20) = 100cms

x = 20/4

x = 5cms

Answer : Lengths of the sides of the squares are 5cms and 20 cms.

Answer 2

Step-by-step explanation:

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