a wire of length 10cm is carrying a current 2A along x axis . a magnetic field exists there which is given by B=2×10-2 the magnitude of magnetic force acting on wire is
Answers
0.4×10^-2 newton
Explanation:
magnetic force=BIL
length(L)=10cm=0.1m
force=2×10^-2×2×0.1
force=0.4×10^-2 newton
The magnitude of the magnetic force acting on wire is 4 × 10^-3 N.
Given: A wire of length 10 cm is carrying a current 2 A along the x-axis. A magnetic field exists which is given by B = 2 × 10^-2 T.
To Find: The magnitude of the magnetic force acting on wire.
Solution:
- The magnetic force between two moving charges may be described as the effect exerted upon either charge by a magnetic field created by the other.
- We can find the magnetic force by implementing the formula given by,
F = ILB sin Ф ...(1)
Where I = current, L = length, B = magnetic field, Ф = angle between the line of flow of current and the magnetic field.
Coming to the numerical, we are given that,
The length of the wire is = 10 cm = 0.1 m
The magnitude of current = 2 A
The magnitude of the magnetic field = 2 × 10^-2 T
So, putting the respective values in (1), we get;
F = ILB sin Ф
⇒ F = 2 × 0.1 × 2 × 10^-2 sin 90° [ sin 90° = 1 ]
⇒ F = 4 × 10^-3 N
Hence, the magnitude of the magnetic force acting on wire is 4 × 10^-3 N.
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