Question

A wire of length 1m 20cm is cut into two equal pieces. One piece is bent to form square and the other one is bent to form rectangle of length 22cm. Compare the areas of the rectangle and the square formed.

Answer 1

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Answer 2

The area of rectangle is smaller than area of square

Step-by-step explanation:

Length of wire = 1 m 20 cm = 100 cm + 20 cm = 120 cm

Wire is divided into two pieces

Length of 1 piece =$\frac{120}{2} = 60 cm$

One piece is bent to form square

Perimeter of square = $4 \times Side$

So, 4 \times Side = 60

Side = 15

Other one is bent to form rectangle of length 22cm.

Perimeter of rectangle = 2(l+b)=2(22+b)

So,2(22+b)= 60

22+b=30

b=8

Area of rectangle = $Length \times Breadth = 22 \times 8 = 176 sq.cm.$

Area of square =$Side^2 = 15^2 = 225 sq.cm.$

Hence The area of rectangle is smaller than area of square

#Learn more:

A wire of length one metre 20 cm is cut into two equal pieces one piece is bent to form a square and the other one band to form a rectangle of length 22cm compare the area of the rectangle and square found​

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