Question

a wire of length 2.5m as percentage strain of 0.012% under a tanside force determine the extension of the wire .
NO SPAMMING PLZZ

Answer 1

Answer:

ORIGINAL LENGTH,L=2.5

STRAIN=AL/L =0.012%

0.012 UPON 100

AL=STAIN×L

OR

AL=EXTENSION =0.012 UPON 100×L

SEE IN THE PIC

=0.012×2.5/100

=3×10 4

=0.3MM

YOUR ANSWER

IS

=0.3MM

Answer 2

Answer

Strain :-

• As mostly tell that strain is ∆l/L where ∆l is the change in length and L is total length. Yeah they correct But strain is not exactly limited to Length.

Strain .......

Change in magnitude/Original Magnitude

ACC to your question

∆L/L = 0.012

L = 2.5m

∆L = (2.5)(0.012)

∆L = 0.03m

Enjoy the quote by me