Question

A wire of length 2 m with the area of cross-
section 10m² is used to suspend a load of
980 N. Calculate i) the stress developed in the
wire ii) the strain and iii) the energy stored.
Given: Y=12 x 10''Nm
-2​

Answer 1

Answer:

2m +10m =12m

980÷12=98

98÷12=81.6

y=12×10

-12-10=

-2