A wire of length 20 cm has a resistance of
2012. If the wire is cut into 10 equal parts,
then find the effective resistance when they
are connected in parallel.
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Answer:
Explanation:
The resistance of a wire depends directly on the length of a wire. thus if we reduce the length of a wire to half the resistance too will drop to half.
thus now two pieces will have 10 ohm resistance each
thus let equivaent resistance in parallel connection be Rq :
Thus 1/Rq = 1/10 +1/10
Rq = 10/2 =5 ohm
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