a wire of length 27 cm is bent in the form of a rectangle in such a way that its length becomes 1 and a half CM less than twice its breadth find the length and the breadth of the rectangle
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Answer:
L = 8.5 cm
B = 5 cm
Step-by-step explanation:
Length of rectangle = L
Breadth of rectangle = B
It's given that
L = 2B - 1½
L = 2B - 1.5
When the wire of 27 cm is bend to form a rectangle then the perimeter of rectangle is equal to 27 cm
Perimeter = 27 cm
2(L + B) = 27
2(2B - 1.5 + B) = 27
2(3B - 1.5) = 27
6B - 3 = 27
6B = 30
B = 5 cm
If B = 5 cm then
L = 2B - 1.5
= (2 × 5) - 1.5
= 10 - 1.5
= 8.5 cm
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