Question

If X=1,y=-1,z=3,a=1,b=-2,c=2 , find the value of X2+y3-3xyz+a2[b-c]​

Answer 1

Step-by-step explanation:

1^2+-1^3-3*1*-1*3+1^2(-2+2)

1-1+3+1(0)

3 answer

Answer 2

Step-by-step explanation:

X=1 y=-1,z=3,a=1,b=-2,c=2

2X+3y-3xyz+2a{b-c}

=2×1+3×(-1)-3(1×(-1)×3)+2(1){-2-2}

=2-3+9-8

=0