a wire of length 36 cm is bent in the form of rectangle such that its length is 7 cm more than its breadth. find the length and the breadth of the rectangle so formed
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Step-by-step explanation:
Given
Perimeter of rectangular wire is 36 cm
So, let breadth of Wire be = x
Hence length of wire = x + 7
Perimeter of rectangle = (l+b)
(x + 7) + (x) = 36
x + 7 + x = 36
2x = 36 - 7
2x = 29
x = 29/2
x = 14.5
Therefore length of wire = x + 7 = 14.5 + 7 = 21.5cm
Breadth of wire = x = 14.5cm
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