Physics, asked by sushmac07, 4 months ago

The pressure in water pipe at the ground floor of a building is 1.5 x 105 Pa, whereas the pressure on fifth floor is 2 x 104 Pa. Calculate the height of the fifth floor. (Take g = 10 ms-2)

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Answered by Anonymous
13

The pressure in water pipe at the ground floor of a building is 1.5 x 105 Pa, whereas the pressure on fifth floor is 2 x 104 Pa. Calculate the height of the fifth floor. (Take g = 10 ms-2)

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Answered by DARLO20
19

\Large\bf{\color{indigo}GiVeN,} \\

  • The pressure in water pipe at the ground floor of a building is 1.5 × 10 La

\longrightarrow\:\:\bf\blue{P_{o}\:=\:1.5\times{10^5}\:Pa} \\

  • The pressure in water pipe on fifth floor is 2 × 10 Pa.

\longrightarrow\:\:\bf\red{P_{(5th\:floor)}\:=\:2\times{10^4}\:Pa} \\

\bf\purple{Let,} \\

  • Height of the 5th floor is 'h' m.

Change in pressure due to height is,

\longmapsto\:\:\bf{\triangle{P}\:=\:P_{o}\:-\:P_{(5th\:floor)}\:} \\

\longmapsto\:\:\bf{\triangle{P}\:=\:15\times{10^5}\:-\:2\times{10^4}\:} \\

\longmapsto\:\:\bf{\triangle{P}\:=\:15\times{10^4}\:-\:2\times{10^4}\:} \\

\longmapsto\:\:\bf\orange{\triangle{P}\:=\:13\times{10^4}\:Pa\:} \\

\bf\pink{We\:know\:that,} \\

\red\bigstar\:\:{\green{\boxed{\bf{\color{peru}\triangle{P}\:=\:{\rho}_{w}\:g\:h\:}}}} \\

\bf\green{Where,} \\

  • \bf{\rho_w} is the density of water, i.e 10³ kg/m³.

  • g is gravitational constant, i.e. 10 m/s².

  • h is the height of the 5th floor.

:\implies\:\:\bf{13\times{10^4}\:=\:\rho_w\:g\:h\:} \\

:\implies\:\:\bf{h\:=\:\dfrac{13\times{10^4}}{\rho_w\:g}\:} \\

:\implies\:\:\bf{h\:=\:\dfrac{13\times{10^4}}{10^3\times{10}}\:} \\

:\implies\:\:\bf{h\:=\:\dfrac{13\times{10^4}}{10^4}\:} \\

:\implies\:\:\bf\blue{h\:=\:13\:m\:} \\

\Large\bold\therefore The height of the 5th floor is 13 m.

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