a wire of length 470 cm and cross section 3.0×10^-9cm^2 stretches by the same amount as a copper wire of length 350 cm and cross section 4.0×10^-9cm^2.find the ratio of youngs modulus of steel to that of a copper.......
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Answers
A Steel wire of length 4.7 m and cross sectional area 3.0 × 10⁻⁵ m² stretches by the same amount as a copper wire of length 3.5 m and cross-sectional area of 4.0 × 10⁻⁵ m² under a given load. What is the ratio of the Young's modulus of Steel to that of Copper?
Answer:
Y₁ : Y₂ = 9 : 5
Explanation:
Given :
For steel wire :
A₁ = 3 × 10⁻⁵ m³ and l₁ = 4.7 m
For copper wire :
A₂ = 4 × 10⁻⁵ m³ and l₂ = 3.5 m
It is said as :
Δl₁ = Δl₂ = Δl and F₁ = F₂ = F
We know :
Y₁ = F₁ l₁ / A₁ Δl₁
= > F / 3 × 10⁻⁵ × 4.7 /Δl
Also Y₂ = F₂ l₂ / A₂ Δl₂
Y₂ = F / 4 × 10⁻⁵ m³ × 3.5 / Δl
We have find ratio of Y₁ / Y₂
Y₁ : Y₂ = ( F / 3 × 10⁻⁵ × 4.7 /Δl ) / ( F / 4 × 10⁻⁵ m³ × 3.5 / Δl )
Y₁ : Y₂ = 4 × 10⁻⁵ × 4.7 / 3 × 10⁻⁵ × 3.5 )
Y₁ : Y₂ = 18.5 / 10.5 ≈ 1.8
Y₁ : Y₂ = 18 / 10 .
Y₁ : Y₂ = 9 : 5
Hence the ratio of the Young's modulus of steel to that of copper 9 : 5