a wire of length 86 centimetre is bent in the form of of a rectangle such that its length is 7 cm more than its breadth. find the length and the breadth of the rectangle so formed.
Answers
Answered by
2
Answer:
Let the length of rectangle=l
⇒ breadth=l−7
⇒ Perimeter of rectangle=2(l+b)= Length of wire
⇒2(l+l−7)=86
⇒2l−7=43
⇒2l=50
⇒l=25cm
⇒ Breadth=18cm.
Explanation:
like my answer
follow me
Answered by
1
Explanation:
L= B + 7cm
2 { L + B } = 86
L + B = 43
B+7 + B = 43
2B = 43-7
2B = 36
B = 18 cm
L = 18 + 7
L = 25 cm
Similar questions