A wire of length 86 cm is bent in the form of a rectangle such that its length is 7 cm more than its breadth. Find the length and the breadth of the rectangle so formed.
Answers
Answered by
40
Let breadth = X and length = X + 7.
Total wire length is also the perimeter of the rectangle.
2(X + X + 7) = 86
2X + 7 = 43
2X = 36
X = 18
X + 7 = 25.
Hence length is 25 cm and breadth is 18cm
Total wire length is also the perimeter of the rectangle.
2(X + X + 7) = 86
2X + 7 = 43
2X = 36
X = 18
X + 7 = 25.
Hence length is 25 cm and breadth is 18cm
Answered by
18
Total length of Wire= Perimeter Of Rectangle
Let Its Breadth = 'x'
So Its Length = 'x+7'
Perimeter Of Rectangle= Total length of Wire [Perimeter = 2(l +b)]
2(x + x +7) = 86
2x + 7 = 86/2
2x + 7 = 43
2x = 43 -7
2x = 36
x = 18 cm
Therfore Breadth = 18cm
Length = x + 7
= 18 + 7
= 25 cm
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