Question

A train starting from rest moves with a uniform acceleration of 0.2 metre per second square for 5 minutes calculate the speed acquired and the distance travelled in this time

Answer 1

v = u + at
= at
= 0.2 * 300
= 60
Speed acquired is 60 m/s

S = 0.5at^2
= 0.5 * 0.2 * (300)^2
= 9000 m
= 9 km

Distance travelled in this time is 9 km

Answer 2

Heya friend,


NOTE-

u=initial velocity
v=final velocity
a=acceleration
t=Time
s=distance

By using 1st equation of motion we will solve the question-


v=u + at
=at
=0.2 * 300
=60

v=60m/s

s=0.5at^2
=0.5 × 0.2 × 300^2
=9000 m
=9 km

So the, Distance travelled in this time is 9 km.


Hope it helps!!!