Question

A train starting from rest moves with a uniform acceleration of 0.2 metre per second square for 5 minutes calculate the speed acquired and the distance travelled in this time

Answer 1

u = 0m/s
a = 0.2m/s²
t = 5 mins = 300sec
using first equation of motion,
v=u+at
v= 0 +0.2(300)
v = 60 m/s

using second equation of motion,
s = ut +1/2 at²
s = 0(300) + 1/2 (0.2)(300)²
s = 0 + 1/2 (0.2)(90000)
s = 9000m or 9 km
hope this helps

Answer 2

v = u + at
= at
= 0.2 * 300
= 60
Speed acquired is 60 m/s
______________

S = 0.5at^2
= 0.5 * 0.2 * (300)^2
= 9000 m
= 9 km

Distance travelled in this time is 9 km