A wire of length 86cm is bent in the form of a rectangle such that it's length is 7cm more than its breadth. Find the length and the breadth of the rectangle so formed.
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As the wire is bent in to rectangle, perimeter of rectangle is equal to length of wire ,
Perimeter = 2×( l + b ) = 86 cm
➡️l + b = 43 cm ......(1)
Given that length is 7cm more than breadth, then
➡️ l = b + 7
Substitute in (1)
b + 7 + b = 43
2b = 36
➡️ b = 18 cm
➡️ l = 25 cm
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