A wire of length I and resistance R is streched to get the radius of cross section halved ? What is the new resistance of th e wire after streching
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Answer:
Resistance becomes 4 times of the original resistance.
Explanation: mark as brainliest
Given: R1= pl/A1
Length=l
Resistivity=p
Area, A2= πr/2²=πr²/4
Resistance, R2= pl/A2
R2=pl/πr²/4
R2= 4pl/πr²
R2= 4R1 (R1=pl/A)
Hence, resistance (R2) becomes 4 times of the original resistance (R1)
Explanation:
Answered by
1
Answer:
Mark me as brainliest
Explanation:
Resistance becomes 4 times of the original resistance.
Explanation:
Given: R1= pl/A1
Length=l
Resistivity=p
Area, A2= πr/2²=πr²/4
Resistance, R2= pl/A2
R2=pl/πr²/4
R2= 4pl/πr²
R2= 4R1 (R1=pl/A)
Hence, resistance (R2) becomes 4 times of the original resistance (R1)
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