Question

A wire, of length L ( = 20cm), is bent into a semicircular arc. If the two equal halves, of the arc, were each to
be uniformly charged with charges ±Q, [|Q|]= 10^3 €coulomb, where € is the permittivity (in SI units) of free
space) the net electric field at the centre O of the semicircular arc would be​

Answer 1

Answer:

A wire, of length L ( = 20cm), is bent into a semicircular arc. If the two equal halves, of the arc, were each to

be uniformly charged with charges ±Q, [|Q|]= 10^3 €coulomb, where € is the permittivity

Explanation:

Here I attached the diagram of the problem soo that one can understand it better.

The answer will be (25×10^3N/C)i^