a wire of length l and cross sectional area A,if the wire is stretched by an amount x then find the workdone
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Work done = 12×12× stress ×× strain ×× volume
=12=12×Y×(strain)2×Volume×Y×(strain)2×Volume
=12=12×Y×(xL)2×Y×(xL)2×AL×AL
=Yx2A2L
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Answer:
Answer is YAx^2/2L
Explanation:
Workdone = 1/2×Y×(stress)^2×volume
= 1/2×Y×x^2/L^2×AL
= 1/2×Y×x^2/L×A
Workdone=Yx^2A/2L
I hope this answer will help you
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