A wire of length l and resistance r is stretched so that its length is doubled and the area of cros section is halved. how will its resistance change
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Let the initial resistance be( Look at the picture)
Now,
Let the resistance after doubling the length and halving the area be R'
R' = rho x 2L / (A/2) = 4 (rho x L / A) = 4R
Resistance increases 4 times.
Hope it helps.
Cheers :)
Now,
Let the resistance after doubling the length and halving the area be R'
R' = rho x 2L / (A/2) = 4 (rho x L / A) = 4R
Resistance increases 4 times.
Hope it helps.
Cheers :)
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