Question

a wire of length L and thickness A has resistance 4 ohm what would be the resistance of a wire made up of same material having same length but of thickness to 2A​

Answer 1

Explanation:

see the attachment....

Answer 2

Answer:

Explanation:

Resistance = p l/a [ p is constant]

For first wire length = l and area of croos section = a

Resistance = p l/a = 4 ohm [given]

For second wire length = l/2 and area of cross section = 2a

Resistance = p (l/2) / 2a

= p l/4a

= p l/a * 1/4 [p l/a = 4 ohm]

= 4*1/4 = 1 ohm

The resistance of second wire = 1 ohm

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