A wire of resistance 1 ohm is elongated by10%.The resistance of the elongated wire?
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resistance of the elongated wire is 1.21Ω
when a wire is elongated, resistance of wire is directly proportional to square of its length.
i.e., R ∝ l²
let initial length of wire is l
wire is elongated by 10% . so, new length of wire is 1.1 l
so, R1/R2 = (l1/l2)²
⇒1 Ω/R2 = (l/1.1l)²
⇒R2 = (1.1)² × 1Ω
⇒R2 = 1.21 Ω
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