A wire of resistance 10 ohm is drawn out so that its length is thrice its originals lenght . Calculate its new resistance
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l₂=3 ˣ l₁
R₁=ρL₁/A
R₂=ρL₂/A
=ρ × 3 l₁/A
=3×ρL₁/A
=3R₁
therefore new resistance = 3 times original resistance
R₁=ρL₁/A
R₂=ρL₂/A
=ρ × 3 l₁/A
=3×ρL₁/A
=3R₁
therefore new resistance = 3 times original resistance
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