A wire of resistance 10 ohms is stretched to thrice.Calculate the new resistance. If this same wire is stretched to reduce its diameter to half of its initial value,what will be new resistance.please explain it....
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R = pl/ A= 10 ohms .......(1)
R'= p3l/A/2
R'= 3×2pl/A
R'= 6 pl/A
that is 6 × 10 from 1
R'= p3l/A/2
R'= 3×2pl/A
R'= 6 pl/A
that is 6 × 10 from 1
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Resistance in ohms (Ω), L is the length in metres (m), A is the area in square metres (m2), and where the proportional constant ρ (the Greek letter “rho”) is known as Resistivity.
Resistance is directly proportional to length and inversely proportional to area.
If the length increases by x%, then Resistance also increases by x%.
i) Say Wire has a resistance of 10Ω; Wire is stretched to 3 times its original length and has a cross-sectional area of 1mm2.
ii) Wire resistance will increase by 3times, 3times of 10Ω=30Ω.
iii) Resistivity will be 10 Ω⋅m.
I hope this answer will help you out and please make me brainlist
Resistance is directly proportional to length and inversely proportional to area.
If the length increases by x%, then Resistance also increases by x%.
i) Say Wire has a resistance of 10Ω; Wire is stretched to 3 times its original length and has a cross-sectional area of 1mm2.
ii) Wire resistance will increase by 3times, 3times of 10Ω=30Ω.
iii) Resistivity will be 10 Ω⋅m.
I hope this answer will help you out and please make me brainlist
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