a wire of resistance 100 ohm and length l is increased to twice it's original length.Calculate its new resistance.
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Answer:
Explanation:
When l is made twice, area of cross section gets halved. Therefore new resistance would be
R=rho*2l/a/2
R=rho*4l/a
R=4(rho*l/a)
R=4(100)
R=400 ohms
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