A wire of resistance 18 ohm is drawn until its radius
reduce ¹/2
reduce 2 of its original radius then resistance of
the wire is
Answers
Answered by
2
Answer:
Let length of wire =1, Area of coress section =A=πr
2
( where r= radius of wire)
Then Resistance, R=ρ
A
1
=ρ
πr
2
1
→(1)
When radius becomes
2
r
then volume would still be same so :
V
1
=V
2
⇒πr
2
l=π(
2
r
)
2
l
2
(where l
2
= new length)
⇒l
2
=4l
So the new resistance R
new
=ρ
A
2
l
2
=ρ
πr
2
4l
×4=16R
But R=18Ω ( given)
⇒R
new
=16×18=288Ω
Explanation:
This is somewhat big but dont mind
This is the correct of all answers
Clarify it.
Clarify and mark me as brainliest if you think this answer is good.
Answered by
0
Answer:
until the 18 ohm radius 98 %sp
shsoha
Explanation:
bosvinbcalhys
Similar questions