Question

A wire of resistance 20 ohm is bent in the form of a closed circle wire. what is the effective resistance b/w the two points at end of any diameter of circle

Answer 1

Final Answer : 5ohm

Steps and Understanding :
1) Since, Diameter divides the circle in two equal parts .
So, each part is of 10ohm. 

2) Both are Parallel along a diameter. 
So, Effective Resistance
$\frac{1}{r} = \frac{1}{10} + \frac{1}{10} \\ = > \frac{1}{r} = \frac{1}{5} \\ = > r = 5ohm$

So, Effective Resistance between ends of a diameter is 5ohm.

Answer 2

Answer:5 ohm

Explanation:Steps and Understanding :

1) Since, Diameter divides the circle in two equal parts .

So, each part is of 10ohm.  

2) Both are Parallel along a diameter.  

So, Effective Resistance

1/r= 1/10+1/10

1/r=1/5

r=5

hope it helps you!!!!!