a wire of resistance 3 ohm and 10 cm is stretched to length 30cm assuming that is has acuniform cross section what will be the new resistance
Answers
Answered by
4
Hi!!!
here is ur answer!!
__________________
as wire of 10 cm length is stretched to 30cm i.e 3 times...
therefore,
resistance becomes 9 times its resistance i. e 3* 9 = 27 ohm
R1 = raw 30/ (a /3 )= 9[ raw 10/a]
R2 = raw 10/ a. (put in above eq.)
R1 = 9R
=> 9*3 = 27ohm...
therefore R = 27 ohm...
hope this helps u!!
here is ur answer!!
__________________
as wire of 10 cm length is stretched to 30cm i.e 3 times...
therefore,
resistance becomes 9 times its resistance i. e 3* 9 = 27 ohm
R1 = raw 30/ (a /3 )= 9[ raw 10/a]
R2 = raw 10/ a. (put in above eq.)
R1 = 9R
=> 9*3 = 27ohm...
therefore R = 27 ohm...
hope this helps u!!
Anonymous:
is it correct??
Answered by
3
Given :- The initial resistance of wire R¹ is 3ohm
When length of the wire is 10cm
It is stretched to length 30cm that means it's length is increased 3 times the initial one.
Resistance is directly proportional to Length of the wire
If we increase the length of the wire the resistance will also increase.
Length is increased 3 times
Resistance will be also increased 3 times
R² = 9ohm
When length of the wire is 10cm
It is stretched to length 30cm that means it's length is increased 3 times the initial one.
Resistance is directly proportional to Length of the wire
If we increase the length of the wire the resistance will also increase.
Length is increased 3 times
Resistance will be also increased 3 times
R² = 9ohm
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