A wire of resistance 4ohm is drawn to twice its orginal length,what is the new resistance
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The new resistance is 16 ohm
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Hey!
Resistance = resistivity*length/area
A wire when drawn to twice its original length,
Let original length be l₁
l₂=2l₁ R₁=4 R₂=??
R₁/R₂=l₁²/(2l₂)²
4/R₂=1/4
R₂=16Ω
Hope it helps^^
Resistance = resistivity*length/area
A wire when drawn to twice its original length,
Let original length be l₁
l₂=2l₁ R₁=4 R₂=??
R₁/R₂=l₁²/(2l₂)²
4/R₂=1/4
R₂=16Ω
Hope it helps^^
Anonymous:
Please mark as brainliest
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