A wire of resistance 5Ω is bent in the form of a closed circle. What is the effective resistance between the two points at the ends of any diameter of the circle?
Answers
Answered by
32
Your answer is --
Given, resistance of wire is 5ohm
since, it is bent in a circle
So, wire is break in two parts and arrange in parallel combination by diameter of circle .
Thus, resitstane of each semi circle wire is 5/2 = 2.5ohm
Therefore , euivalent resistance is
1/R = 1/2.5 + 1/2.5
=> 1/R = 2/2.5
=> R = 2.5/2
=> R = 1.25ohm
Hence, effective resistance between the two points at the ends of any diameter of the circle is 1.25ohm
【 Hope it helps you 】
Given, resistance of wire is 5ohm
since, it is bent in a circle
So, wire is break in two parts and arrange in parallel combination by diameter of circle .
Thus, resitstane of each semi circle wire is 5/2 = 2.5ohm
Therefore , euivalent resistance is
1/R = 1/2.5 + 1/2.5
=> 1/R = 2/2.5
=> R = 2.5/2
=> R = 1.25ohm
Hence, effective resistance between the two points at the ends of any diameter of the circle is 1.25ohm
【 Hope it helps you 】
Attachments:
Normal0Student:
Thank you so much!
Similar questions