A wire of resistance R and length L is compressed to one third of it's original length. New resistance of wire is
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Answer:
resistance decrease bi 9 Times
Explanation:
R is directly proportional to (length)²
let R=k(L)²
and R(new)=k(L/3)²
therefore , R(old) /R(new) = 9
that implies R(new)=R(old)/9
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