. A wire of resistance ‘R’ is stretched by 50%. What will be percentage change in it’s resistance?
Answers
Answered by
114
The resistance of a wire increases with length. This is because resistance is directly proportional to to the length of the wire.
The formula for resistance(R) = resistivity(r)x Length (L)/Area (A)
initial length = L
new length = 150/100L =1.5L
new R = rx1.5L/A =1.5rL/A
The initial R= 100% = rL/A
rL/A= 100%
1.5rL/A= (100 x 1.5rL/A x A/rL)%
= 1.5 x100
=150% (new R)
Therefore the Resistance increases by 50%
The formula for resistance(R) = resistivity(r)x Length (L)/Area (A)
initial length = L
new length = 150/100L =1.5L
new R = rx1.5L/A =1.5rL/A
The initial R= 100% = rL/A
rL/A= 100%
1.5rL/A= (100 x 1.5rL/A x A/rL)%
= 1.5 x100
=150% (new R)
Therefore the Resistance increases by 50%
Answered by
30
Answer: Santy2 answer will definitely fail you in the exam
The answer is 125 %
Explanation: L2 = L1 +50/100L1 = 150L1/100
L2= 1.5 L1
R2/R1 = (L2/L1)². R2/R1 =( 1.5L1/L1 )²
R2/R1 = 2.25 ...... R2 = 2.25R1
Change in resistance R= R2 - R1 ......
2.25R1 - R1 = R1(2.25 - 1) = R1*1.25
Change in resistance = changed resistance/original resistance * 100 %
= 125%
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