A wire of resistance R is stretched to twice its original length. Its new resistance will be
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Answer:
4R
Explanation:
This is the answer considering that area also changes.
As R=ρ (L/A)
Therefore on stretching the wire volume remains constant which means L₁A₁=L₂A₂
From here we get that A₂ = A₁/2.
Putting value we get R' = ρ (2L/A/2) = ρ4 ( L/A)
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