A wire of resistance R1 is cut into 5 equal pieces this 5 pieces of wires then connected in parallel if the resultant resistance of the combination is R2 then find the value of R1/ R2 ?
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Hi..
When cut into 5 pieces, resistance of each part is R/5.
So, equivalent resistance of the 5 pieces when connected in parallel is, 1/R1 = 5/R + 5/R + 5/R + 5/R + 5/R
=> R1 = R/25
So, required ratio is, R : R1 = 25 :1..
Hope this helps u!
When cut into 5 pieces, resistance of each part is R/5.
So, equivalent resistance of the 5 pieces when connected in parallel is, 1/R1 = 5/R + 5/R + 5/R + 5/R + 5/R
=> R1 = R/25
So, required ratio is, R : R1 = 25 :1..
Hope this helps u!
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