Factorise
21x^2+5x-6
Answers
Answered by
93
Answer :
Now,
21 x² + 5 x - 6
= 21 x² + ( 14 - 9 ) x - 6
= 21 x² + 14 x - 9 x - 6
= 7 x ( 3 x + 2 ) - 3 ( 3 x + 2 )
= ( 3 x + 2 ) ( 7 x - 3 ),
which is the required factorization.
#MarkAsBrainliest
Now,
21 x² + 5 x - 6
= 21 x² + ( 14 - 9 ) x - 6
= 21 x² + 14 x - 9 x - 6
= 7 x ( 3 x + 2 ) - 3 ( 3 x + 2 )
= ( 3 x + 2 ) ( 7 x - 3 ),
which is the required factorization.
#MarkAsBrainliest
Answered by
13
Hello!
=> 21x² + 5x - 6 = 0
= Using quadratic formula
=> D = b² - 4ac
= D = 25 - 4 (21) (-6)
D = 25 + 504
√D = √529
D = 23
=> x = - b + √D / 2a and - b - √D / 2a
= x = -5 + 23 / 21 x 2 and -5 - 23 / 21 x 2
= x = 18 / 42 and -28 / 42
= x = 3 / 7 and -2 / 3
I hope it helped.
Mark it as BRAINLIEST.
Thank You !
=> 21x² + 5x - 6 = 0
= Using quadratic formula
=> D = b² - 4ac
= D = 25 - 4 (21) (-6)
D = 25 + 504
√D = √529
D = 23
=> x = - b + √D / 2a and - b - √D / 2a
= x = -5 + 23 / 21 x 2 and -5 - 23 / 21 x 2
= x = 18 / 42 and -28 / 42
= x = 3 / 7 and -2 / 3
I hope it helped.
Mark it as BRAINLIEST.
Thank You !
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