A wire of uniform thickness with a resistance of 27 is cut into three equal pieces and they are joined in parallel. Find the resistance of the parallel combination.
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Answer:
Net Resistance R=9 Ohm
Explanation:
Since it is given, the wire is of uniform thickness.So, the area of this particular wire is Uniform
I.e A=Constant
A/Q.....the wire is further divided into 3 equal parts and is connected in parallel to one another.
So, we know 1/R=1/R1+1/R2+1/R3
Each cutted down wire having 27 ohm each
So, Net Resistance becomes,....
1/R=1/27+1/27+1/27
=3/27
=1/9
So,Net R becomes 9 Ohm.....
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