A wire when bent in the form of a square, encloses an area of 441cm^2. If the same wire is bent to form a circle, what will be the radius of the circle so formed?
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let side of the square = a cm
i) area of the square formed by the wire = 441cm²
a² = 441cm²
a²=(21cm)²
a= 21 cm----(1)
perimeter of the square = 4a= 4*21 =84 cm----(2)
ii)circumference of the circle formed by same wire = perimeter of the square
⇒2πr = 84 [here r is radius of the circle]
⇒2*22/7 r =84
⇒r = (84*7)/(2*22)
r=147/11cm
i) area of the square formed by the wire = 441cm²
a² = 441cm²
a²=(21cm)²
a= 21 cm----(1)
perimeter of the square = 4a= 4*21 =84 cm----(2)
ii)circumference of the circle formed by same wire = perimeter of the square
⇒2πr = 84 [here r is radius of the circle]
⇒2*22/7 r =84
⇒r = (84*7)/(2*22)
r=147/11cm
mysticd:
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