A wire when bent in the form of a square encloses an area of 196 cm^2 .If the same wire is bent to formally a circle,find the area of the circle.
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area of square=(side)^2
so side=sqrt(area)
in this case, area=196cm^2.
so side=14cm.
then, perimeter=14*4=56cm
this is also the circumference of the circle.
so, 2*pi*r=56
and r=8.91
so, area=pi*r*r=250cm^2..
hope you like it..
mark me as brainliest as i need it.
so side=sqrt(area)
in this case, area=196cm^2.
so side=14cm.
then, perimeter=14*4=56cm
this is also the circumference of the circle.
so, 2*pi*r=56
and r=8.91
so, area=pi*r*r=250cm^2..
hope you like it..
mark me as brainliest as i need it.
Answered by
0
Given Area of square = 196cm^2.
a^2 = 196
a = 14 cm.
Perimeter of square = 4 * a
= 4 * 14
= 56.
Given that Perimeter of square of perimeter of circle
56 = 2pir
pir = 28
r = 28 * 7/22
= 196/22
= 98/11.
Area of circle = pi * r * r
= 22/7 * 98/11 * 98/11
= 124.72 sq.cm.
Hope this helps!
a^2 = 196
a = 14 cm.
Perimeter of square = 4 * a
= 4 * 14
= 56.
Given that Perimeter of square of perimeter of circle
56 = 2pir
pir = 28
r = 28 * 7/22
= 196/22
= 98/11.
Area of circle = pi * r * r
= 22/7 * 98/11 * 98/11
= 124.72 sq.cm.
Hope this helps!
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