Question

A wire when bent in the form of an equilateral triangle encloses an area of 121 root 3cm square. If the wire is bent in the form of circle, find the area encloses by the circle

Answer 1

Answer:

346.5 cm^2

Step-by-step explanation:

Area of an equilateral triangle = ((√3 )/4 )Side^2

((√3 )/4 )Side^2 = 121 √3  cm^2

side^2 = 121 * 4 cm^2

Side = 11 * 2 cm

side = 22cm

Perimeter of triangle = 3*22 = 66 cm

Perimeter of circle = 2 * Pie * R

2* Pie * R = 66

R = 33 / Pie

Area of circle = Pie * R^2

= Pie * (33/Pie)^2

= 33^2 / Pie

= 33 * 33 / (22/7)

= 33 * 33 * 7 / 22

= 3 * 33 * 7 / 2

= 693/2

= 346.5 cm^2

Answer 2

Area of circle is 346.5 square cm.