Question

A wire, which passes through the hole in a small bead, is bent in the form of quarter of a
circle. The wire is fixed vertically on ground as shown in the figure. The bead is released
from near the top of the wire and it slides along the wire without friction. As the bead
moves from A to B, the force it applies on the wire is
(A) always radially outwards.
(B) always radially inwards.
(C) radially outwards initially and radially inwards later.
(D) radially inwards initially and radially outwards later.

Answer 1

Hello !
The answer to your question is option D.
Explanation
 Now the tendency of the bead is to go down but the wire resists it to do so .
The magnitude of the force acting vertically downwards is more than the horizontal force  
And slowly the force acting horizontally will increase
So it will initially move inwards and when the bead will arrive the half length of the wire the horizontal force is much and then it will resist the tendency of the bead to move inwards and then it will move outwards.
I hope u understood  my explanation !
Thank you !