A woman has 60 notes in all rs.10 amd rs.20 of denomination .if the total worth of the notes is rs.850 find out how many notes of each kind does she have
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Answered by
29
x+y=60,10x+20y=850 solving both
10(60-y)+20y=850
10y=250
y=25
and x=35 so 10 rupee notes is 35
and 20 rupee notes is 25
10(60-y)+20y=850
10y=250
y=25
and x=35 so 10 rupee notes is 35
and 20 rupee notes is 25
Answered by
86
hi
A woman has 60 notes in all rs.10 amd rs.20
let no .of 10rs be x and 20 be y
x +y = 60
x = 60 - y
now
the total money was 850 rs
so
10x +20y = 850
now, since x = 60 - y
10x +20y = 850
10(60 - y) + 20y = 850
600 - 10y + 20y = 850
600 +10y = 850
10y = 250
y = 25
now x = 70 - y
= 70 - 25
= 35
so 10 rs notes = 35 and 20 rs notes = 25
:)
A woman has 60 notes in all rs.10 amd rs.20
let no .of 10rs be x and 20 be y
x +y = 60
x = 60 - y
now
the total money was 850 rs
so
10x +20y = 850
now, since x = 60 - y
10x +20y = 850
10(60 - y) + 20y = 850
600 - 10y + 20y = 850
600 +10y = 850
10y = 250
y = 25
now x = 70 - y
= 70 - 25
= 35
so 10 rs notes = 35 and 20 rs notes = 25
:)
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