Question

a woman is 7 times as old as her son after 5 years it will be 4 times as old as his son what are the present age of the mother and son​

Answer 1

$let \: the \:present \: age \: of \: son \: be \: x$

$mother \: present \: age = 7x$

$after \: five \: year$

$son \: age = x + 5$

$mother \: age = 7x + 5$

$4(x + 5) = 7x + 5 \\ = > 4x + 20 = 7x + 5 \\ = >20 - 5 = 7x - 4x \\ = > 15 = 3x \\ = > x = \frac{15}{3} = 5$

$son \: present \: age = 5 \: years \\ mother \:present \: age = 7 \times 5 = 35 \: years$

Answer 2

Let the present age of son be x

the present age of women be 7x

After 5 years,

Son age = x+5

Women age = 7x+5

A/Q

$4(x + 5) = 7x + 5 \\ 4x + 20 = 7x + 5 \\ 15 = 3x \\ x = 5$

:. Son age = 5 years

:. Women age = 7× 5 = 35 years