Question

Angle ACB is inscribed angle in arc ACB of a circle with centre O.If Angle ACB=65°,find m(arcACB)

Answer 1

Answer:

m (arcACB) = 130°

Explanation:

By theorem of inscribed angle

m (<ACB) = 1/2 × m (arcACB)

65° = 1/2 × m (arcACB)

65° × 2 = m (arcACB)

m (arcACB) = 130°