Question

A woman is three times as old as her daughter. six years ago, the sum of their ages was 36. find the age of the daughter.​

Answer 1

let the age of daughter be 'x'.

Thus, the age of woman = 3x

6 yrs ago, the sum of their ages was 36.

or, 3x + x = 36

or, 4x = 36

or, x = (36 / 4)

= 9

Thus, the age of daughter is 9 yrs.

Answer 2

Answer:

12 years

Step-by-step explanation:

let the daughter's age be x

and the mother's age be 3x

six years ago the sum of their age was 36

this, (3x-6) + (x-6) = 36

3x-6+x-6=36

collecting like terms

3x+x=36+6+6

4x=48

dividing both sides by 4

4x/4 = 48/4

x=12

therefore, the daughter's age is 12 years.