Two point charges qA = 3 μC and qB = −3 μC are located 20 cm apart in vacuum.
(a) What is the electric field at the midpoint O of the line AB joining the two charges?
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a) The situation is represented in the given figure. O is the mid-point of line AB.
Distance between the two charges, AB = 20 cm
∴ AO = OB = 10 cm
Net electric field at point O = E
Electric field at point O caused by +3μC charge,
Where, 0 = Permittivity of free space and 1/4πεo=9×109 Nm2C−2
Therefore,
Magnitude of electric field at point O
Therefore, the electric field at mid-point O is 5.4 × 106 N C−1 along OB.
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